Mean

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Mean
Message posted by Kevin (via 64.252.206.140) on December 18, 2001 at 2:56 PM (ET)

A dishonest coin with probability of heads p=0.2 is tossed n times. Let the random variable X denote the number of heads tossed. Find the mean so that there is 95% chance that X will be between n/5-20 and n/5+20. Can someone show me how this is done?

READERS RESPOND:
(In chronological order. Most recent at the bottom.)

Re: Mean
Message posted by JG (via 128.8.23.230) on December 18, 2001 at 5:47 PM (ET)

651

Re: Mean
Message posted by Kevin (via 64.252.205.8) on December 19, 2001 at 8:49 AM (ET)

Thats great JG, but it tells me nothing. I would like to know how you come up with that answer? What formulas can I use?

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