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Home > Statistics Every Writer Should Know > The Stats Board > Discusssion
probability distribution
I am on my 3rd unit in stats math Probability Distribution and my assignment is asking an assortment of questions, I'm assuming preparing me for my mid term, however, i am so lost in this it isn't even funny. the question is: Out of a random sample of 33 students of which 10 are in their 30's, 15 in their 40's, 5 in their 50's and 3 in their 60's.Let x be the age.
READERS RESPOND: Re: probability distribution For the expected value, you use E(X) = sum (P(X_i)*X_i) Assume that the mid-range value of "people in their 30's" is 35 etc. Expected value = 35*(10/33) + 45*(15/33) + 55*(5/33) + 65*(3/33) = 350/33 + 675/33 + 275/33 + 195/33 = 1495/33 = 45.303 = 45 years (nearest year). 15 in their 40's, 5 in their 50's and 3 in their 60's.Let x be the age.
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